The math is here: https://andorstrail.com/viewtopic.php?t=6613. It is correct.Anku wrote: Tue Jan 07, 2025 3:31 am WORK IN PROGRESS! WORKING ON A GOOGLE SHEETS DOC TO DO THE MATH FOR YOU, THE MATH BELOW IS INCORRECT. DO NOT USE IT!
v0.8.12.1 ("Towards Feygard" or "Of kobolds, fae, witch and troll", including bugfix) released to Google Play!
Useful links
Source code of the game - Contribution guide - ATCS Editor - Translate the game on Weblate - Example walkthrough - Andor's Trail Directory - Join the Discord
Get the game (v0.8.12.1) from Google, F-Droid, our server, or itch.io
Useful links
Source code of the game - Contribution guide - ATCS Editor - Translate the game on Weblate - Example walkthrough - Andor's Trail Directory - Join the Discord
Get the game (v0.8.12.1) from Google, F-Droid, our server, or itch.io
Extraordinary and legendary items
- rijackson741
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Re: Magic Finder, Not For the Faint of Heart
Level:75, XP:7656192, PV:866, FQ:105
HP:226, AC:255, AD:47-61, AP:3, ECC:23%, CM:3.0, BC:192, DR:3
Gold: 241432 | RoLS:1, RoL:1, GoW:1, VSH:1, RoFLS:1, WoB:1
HH:1, WA:1, D:1, CS:2, Cl:1, IF:4, Ev:3, Re:2, WP:DA:1, WP:1S:1, WP:B:1, AP:L:1, FS:DW:2, S:DW:1
HP:226, AC:255, AD:47-61, AP:3, ECC:23%, CM:3.0, BC:192, DR:3
Gold: 241432 | RoLS:1, RoL:1, GoW:1, VSH:1, RoFLS:1, WoB:1
HH:1, WA:1, D:1, CS:2, Cl:1, IF:4, Ev:3, Re:2, WP:DA:1, WP:1S:1, WP:B:1, AP:L:1, FS:DW:2, S:DW:1
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Re: Extraordinary and legendary items
This is not how probability works. Even though every monster has a fixed drop chance based on your Magic Finder level, your chances of obtaining the item DO increase the more monsters youve killed. The formula is: P(A) = 1 - (1 - p)^n when accounting for an unchanged Magic Finder level throughout your hunt. P(A) is the Probability of obtaining the item. p is the drop chance of the monster. n is how many monsters you killed.Canuck wrote: Tue Jan 07, 2025 9:07 pm The main point is that the monsters you've already killed don't count. You're always starting from zero, no matter how many hundreds or thousands you've already killed.
But I agree that these kinds of calculations can be fun, if only to get a sense in retrospect of how far your experience was from the centre of the curve.
Also, you can achieve a 100% drop rate for Extraordinary items by upgrading Magic Finder 18 times for Extraordinary items (this would require 72 character levels) or 198 times (792 character levels) for Legendary Items. It is true that you can never achieve a 100% chance to obtain the item without a 100% drop chance.
However the fact remains that the probability of obtaining the item does in fact increase the more monsters youve killed. We can use the Inclusion Exclusion Principle to determine the probability for any hunt that includes multiple Magic Finder levels throughout your hunt: e.g started with Magic Finder 2, but upgrade your Magic Finder 2 or 3 times before you received the item.
That's what the spreadsheet I just posted does. Unlike the other AT game mechanic posts, this spreadsheet accounts for multiple different levels of Magic Finder, and calculates the probability of obtaining the item based on what you input for monsters killed. The Andors Trail game mechanics post does not account for multiple MF lvls when calculating the total probability. My spreadsheet can give you the total probability of anywhere from 0 to 20 Magic Finder levels, and any combination of them as well.
The only catch is, you have to know approximately how many monsters you killed per each Magic Finder lvl.
Last edited by Anku on Thu Jan 09, 2025 9:14 pm, edited 1 time in total.
- Nut
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Re: Extraordinary and legendary items
Well, you are both right. Probability is a strange thing.
If you haven't started yet, the probability to get at least 1 ring after 1 mio kills is rather high.
BUT if you have done 999999 kills with no ring, the probability to get it on next kill is still 0.01%
If you haven't started yet, the probability to get at least 1 ring after 1 mio kills is rather high.
BUT if you have done 999999 kills with no ring, the probability to get it on next kill is still 0.01%
Nut
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Re: Extraordinary and legendary items
Exactly. Anku's probabilities apply only ex-ante, not ex-post.
The monsters you've already killed don't count, because the uncertainty has resolved itself. Whether you already killed 0 or 10,000 monsters makes no difference in the probabilities: they apply only to the monsters you haven't killed yet.
More here, for anyone interested:
https://en.wikipedia.org/wiki/Gambler's_fallacy
The monsters you've already killed don't count, because the uncertainty has resolved itself. Whether you already killed 0 or 10,000 monsters makes no difference in the probabilities: they apply only to the monsters you haven't killed yet.
More here, for anyone interested:
https://en.wikipedia.org/wiki/Gambler's_fallacy
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Re: Extraordinary and legendary items
[*][/strike][/strike]
P(A) = 1 - (1 - p)^n
P(A): Probability for rolling a 6
p: chance of getting a 6 (1/6)
n: number of times I rolled (100)
Probability of rolling a 6 after 100 rolls = 99.99999%
The gamblers fallacy simply means that the more you do independent events, you can never achieve 100%
Yes, but just like people confuse independent events with dependent ones, which is what the gamblers fallacy is, many people also misunderstand the gamblers fallacy. The gamblers fallacy does not mean that the more times you do something the probability doesn't increase. If I rolled a dice 100 times, and was trying to get a 6, I would use this formula for independent events to determine the chances I would have rolled a 6 by now:Canuck wrote: Thu Jan 09, 2025 7:32 pm Exactly. Anku's probabilities apply only ex-ante, not ex-post.
The monsters you've already killed don't count, because the uncertainty has resolved itself. Whether you already killed 0 or 10,000 monsters makes no difference in the probabilities: they apply only to the monsters you haven't killed yet.
More here, for anyone interested:
https://en.wikipedia.org/wiki/Gambler's_fallacy
P(A) = 1 - (1 - p)^n
P(A): Probability for rolling a 6
p: chance of getting a 6 (1/6)
n: number of times I rolled (100)
Probability of rolling a 6 after 100 rolls = 99.99999%
The gamblers fallacy simply means that the more you do independent events, you can never achieve 100%
Last edited by Anku on Thu Jan 09, 2025 9:51 pm, edited 4 times in total.
- rijackson741
- Posts: 4491
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Re: Extraordinary and legendary items
The occurrences in AT are independent. The monsters you have killed have no influence on the current probability of a drop, regardless of what level of MF you had, or have.
if you have had several levels of MF the calculation for the probability that you would have had a drop at some point is fairly simple. If the probability of getting a drop with MF0 is P0, the probability of getting a drop with MF1 is P1, etc. (the spreadsheet I posted will calculate those probabilities for you if you enter the level of MF and you know the number of kills with that level of MF) then the probability of a drop is
P=1-(1-P0)*(1-P1)*(1-P2)...
if you have had several levels of MF the calculation for the probability that you would have had a drop at some point is fairly simple. If the probability of getting a drop with MF0 is P0, the probability of getting a drop with MF1 is P1, etc. (the spreadsheet I posted will calculate those probabilities for you if you enter the level of MF and you know the number of kills with that level of MF) then the probability of a drop is
P=1-(1-P0)*(1-P1)*(1-P2)...
Level:75, XP:7656192, PV:866, FQ:105
HP:226, AC:255, AD:47-61, AP:3, ECC:23%, CM:3.0, BC:192, DR:3
Gold: 241432 | RoLS:1, RoL:1, GoW:1, VSH:1, RoFLS:1, WoB:1
HH:1, WA:1, D:1, CS:2, Cl:1, IF:4, Ev:3, Re:2, WP:DA:1, WP:1S:1, WP:B:1, AP:L:1, FS:DW:2, S:DW:1
HP:226, AC:255, AD:47-61, AP:3, ECC:23%, CM:3.0, BC:192, DR:3
Gold: 241432 | RoLS:1, RoL:1, GoW:1, VSH:1, RoFLS:1, WoB:1
HH:1, WA:1, D:1, CS:2, Cl:1, IF:4, Ev:3, Re:2, WP:DA:1, WP:1S:1, WP:B:1, AP:L:1, FS:DW:2, S:DW:1
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Re: Extraordinary and legendary items
rijackson741 wrote: Thu Jan 09, 2025 8:30 pm The occurrences in AT are independent. The monsters you have killed have no influence on the current probability of a drop, regardless of what level of MF you had, or have.
if you have had several levels of MF the calculation for the probability that you would have had a drop at some point is fairly simple. If the probability of getting a drop with MF0 is P0, the probability of getting a drop with MF1 is P1, etc. (the spreadsheet I posted will calculate those probabilities for you if you enter the level of MF and you know the number of kills with that level of MF) then the probability of a drop is
P=1-(1-P0)*(1-P1)*(1-P2)...
Yes I misunderstood what independent and dependent meant. I knew each kill was an independent event, but I thought that because when u kill 300 monsters with Magic Finder 2 and 500 with magic finder 3, and the game still counts total monsters killed as 800 that the combination of both events was "dependent". I didn't realize that dependent in this context would mean that the 500 monsters killed with Magic Finder 3 would retroactively or dynamically alter the chances of the the previous 300 monsters with Magic Finder two. Luckily, the spreadsheet I created correctly assumes the events are independent. I am editing my previous post now.
Last edited by Anku on Thu Jan 09, 2025 9:50 pm, edited 2 times in total.
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Re: Extraordinary and legendary items
Omg, when I read your formula I was so worried that my spreadsheet was incorrect, because I used the inclusion exclusion principle formula for it:rijackson741 wrote: Thu Jan 09, 2025 8:30 pm The occurrences in AT are independent. The monsters you have killed have no influence on the current probability of a drop, regardless of what level of MF you had, or have.
if you have had several levels of MF the calculation for the probability that you would have had a drop at some point is fairly simple. If the probability of getting a drop with MF0 is P0, the probability of getting a drop with MF1 is P1, etc. (the spreadsheet I posted will calculate those probabilities for you if you enter the level of MF and you know the number of kills with that level of MF) then the probability of a drop is
P=1-(1-P0)*(1-P1)*(1-P2)...
P(A or B) = P(A) + P(B) - P(A and B)
Luckily, when writing the script for my spreadsheet, it assumes all events are independent (thank God I didn't make them dependent), and thus the two formulas are analogous and produce the same result.
No rewriting script for me! The spreadsheets math is correct!!!! Yayyy!!!
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Re: Extraordinary and legendary items
The main point of the Gambler's Fallacy is that past probabilities don't affect future probabilities.Anku wrote: Thu Jan 09, 2025 8:09 pmThe gamblers fallacy simply means that the more you do independent events, you can never achieve 100%
If you haven't started rolling the dice yet, the chance of rolling a 6 at some point in the next 100 rolls is (as you mention) something close to 99.99999%.
If you've already rolled the dice 99 times without getting a 6, the chance of getting a 6 on the 100th roll remains 1 ÷ 6, or approximately 16.7%.
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Re: Extraordinary and legendary items
I have a love/hate for you right now. OMG ugggghhhh. Based on your formula you just provided:rijackson741 wrote: Thu Jan 09, 2025 8:30 pm The occurrences in AT are independent. The monsters you have killed have no influence on the current probability of a drop, regardless of what level of MF you had, or have.
if you have had several levels of MF the calculation for the probability that you would have had a drop at some point is fairly simple. If the probability of getting a drop with MF0 is P0, the probability of getting a drop with MF1 is P1, etc. (the spreadsheet I posted will calculate those probabilities for you if you enter the level of MF and you know the number of kills with that level of MF) then the probability of a drop is
P=1-(1-P0)*(1-P1)*(1-P2)...
P=1-(1-P0)*(1-P1)*(1-P2)
I was able to write a simple equation in the function bar on Google Sheets that does the EXACT same thing as my 70 line script does, which took me 3 days to write btw... THE EXACT SAME MATH, but way simpler. I spent all that time researching inclusion exclusion principle, trying to find spreadsheets that had it incorporated, or pre existing functions, only to end up spending 3 DAYS writing a script for it that I DIDNT EVEN NEED! AHHHHHHH!!! I'm so frustrated. Here is the equation you can put into the function bar, if you want to add it to the game mechanics spreadsheet that you quoted earlier, so people can determine chances based on multiple Magic Finder levels. The equation accounts for blank cells.
=IF(COUNT(F2:F22) = 0, "", ROUND((1 - PRODUCT(ARRAYFORMULA(IF(F2:F22<>"", 1 - F2:F22, 1)))) * 100, 2) & "%")
You would obviously replace F2 and F22 with whatever cells you have designated on the spreadsheet. Hope you incorporate it!